physics

The potential difference between the accelerating plates of a TV set is about 30 kV. If the distance between the plates is 1.1 cm, find the magnitude of the uniform electric field in the region between the plates. (in N/C)

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  1. E = - grad φ
    For 1D case
    E = Δφ/d = 30000/0.011 = 2.73•10^-6 N/C

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  2. 2.72*10^6

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