The potential difference between the accelerating plates of a TV set is about 30 kV. If the distance between the plates is 1.1 cm, find the magnitude of the uniform electric field in the region between the plates. (in N/C)
E = - grad φ
For 1D case
E = Δφ/d = 30000/0.011 = 2.73•10^-6 N/C
2.72*10^6
To find the magnitude of the uniform electric field between the plates, we can use the formula:
Electric field (E) = Potential difference (V) / Distance between the plates (d)
Given:
Potential difference (V) = 30 kV = 30,000 V
Distance between the plates (d) = 1.1 cm = 0.011 m
Substituting the values into the formula, we have:
Electric field (E) = 30,000 V / 0.011 m
Electric field (E) = 2,727,272.727 N/C
Therefore, the magnitude of the uniform electric field in the region between the plates is approximately 2,727,272.727 N/C.
To find the magnitude of the uniform electric field between the plates, we can use the formula:
Electric field (E) = Potential difference (V) / Distance between the plates (d)
First, we need to convert the potential difference from kilovolts (kV) to volts (V):
30 kV = 30,000 V
Now we can substitute the values into the formula:
E = 30,000 V / 1.1 cm
However, it is important to note that we need to convert the distance from centimeters (cm) to meters (m) because the SI unit for electric field is Newtons per Coulomb (N/C):
1.1 cm = 0.011 m
Now we can calculate the electric field:
E = 30,000 V / 0.011 m
E ≈ 2,727,272.73 N/C
Therefore, the magnitude of the uniform electric field in the region between the plates is approximately 2,727,272.73 N/C.