Na + H2O �¨ NaOH + H2
How many moles of H2 would be formed from 30 grams of Na in the following (UNBALANCED) equation?
How many moles of H2 would be formed from 30 grams of Na in the following (UNBALANCED) equation?
Na + H2O → NaOH + H2
To determine the number of moles of H2 formed from 30 grams of Na, we need to use the balanced equation for the reaction:
2Na + 2H2O → 2NaOH + H2
From the balanced equation, we can see that for every 2 moles of Na, 1 mole of H2 is produced.
To find the number of moles of Na, we can use the formula:
moles = mass / molar mass
The molar mass of Na is 22.99 g/mol.
moles of Na = 30 g / 22.99 g/mol
moles of Na ≈ 1.30 mol
Since the reaction is 2:1 for Na to H2, the number of moles of H2 formed is half the number of moles of Na:
moles of H2 = 1.30 mol / 2
moles of H2 ≈ 0.65 mol
Therefore, approximately 0.65 moles of H2 would be formed from 30 grams of Na in the given reaction.
To determine the number of moles of H2 formed from 30 grams of Na, we need to first balance the equation and then use stoichiometry to find the number of moles.
Balanced Equation:
2 Na + 2 H2O -> 2 NaOH + H2
The balanced equation indicates that 2 moles of Na react to produce 1 mole of H2. Therefore, we can set up a proportion to find the number of moles of H2 produced.
Proportion:
2 moles Na / 1 mole H2 = 30 grams Na / x moles H2
To find x (the number of moles of H2), we can rearrange the proportion to solve for x:
x = (30 grams Na) * (1 mole H2 / 2 moles Na)
Now we can calculate the number of moles of H2:
x = (30 grams Na) * (1 mole H2 / 2 moles Na)
x = 15 grams H2
Therefore, 30 grams of Na would produce 15 grams of H2, or equivalently, 15 moles of H2.
2Na + 2H2O == 2NaOH + 2H2
mols Na = grams/atomic mass
Convert mols Na to mols H2 using the coefficients in the balanced equation. That's 2:2 therefore, mols H2 = mols Na.