4 moles CO, 5 moles N2 and 2 moles C2H4 are placed in a 5 liter vessel at 27 degree celsius . the ratio of kinetic energy per molecule of CO2, He and NH3 is

To find the ratio of kinetic energy per molecule of CO2, He, and NH3, we need to compare the average kinetic energies of the gases.

The average kinetic energy of a gas can be calculated using the formula:

KE_avg = (3/2) * k * T

Where:
KE_avg is the average kinetic energy
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin

First, we need to convert the temperature from Celsius to Kelvin:

T(K) = T(C) + 273.15

So, T(K) = 27 + 273.15 = 300.15 K

Now we can calculate the average kinetic energy for each gas:

For CO2:
KE_avg_CO2 = (3/2) * k * T(K)

For He:
KE_avg_He = (3/2) * k * T(K)

For NH3:
KE_avg_NH3 = (3/2) * k * T(K)

Since the kinetic energy is proportional to the temperature, the ratio of kinetic energies will be the same as the ratio of temperatures.

So, the ratio of kinetic energy per molecule of CO2, He, and NH3 is:

KE_avg_CO2 : KE_avg_He : KE_avg_NH3 = T(K) : T(K) : T(K)

Therefore, the ratio is 1:1:1.