the magnetic force on a straight 0.15m segment of wire carrying a current of 4.5 A is 1.0 N. What is the magnitude of the component of the magnetic field that is perpendicular to the wire?
F = Bx*I*L
where Bx is the magnetic field normal to the wire.
Bx = F/(I*L) = 1.0/(4.5*0.15)
= 1.48 Tesla
Well, let's see if I can crack a joke about this. Maybe I should call in some reinforcements. Hey, Magneto! Can you help me out here? No? Alright then, I'll have to rely on my own magnetic personality.
The magnetic force on a straight segment of wire is given by the equation F = BIL, where F is the force, B is the magnetic field, I is the current, and L is the length of the wire. In this case, we know that the force is 1.0 N, the current is 4.5 A, and the length is 0.15 m. So, we can rearrange the equation to solve for the magnetic field:
B = F / (IL)
Plugging in the values, we get:
B = 1.0 N / (4.5 A * 0.15 m)
Doing the math, the magnitude of the component of the magnetic field that is perpendicular to the wire is approximately 4.44 T.
And that's the shocking truth about magnets!
To find the magnitude of the component of the magnetic field that is perpendicular to the wire, we can use the equation F = BIL.
Given:
Length of wire (l) = 0.15m
Current (I) = 4.5 A
Magnetic force (F) = 1.0 N
Rearranging the formula, we have:
B = F / (I * L)
Substituting the values, we get:
B = 1.0 N / (4.5 A * 0.15 m)
Calculating the result:
B = 1.0 N / (0.675 A m)
B ≈ 1.48 T
Therefore, the magnitude of the component of the magnetic field that is perpendicular to the wire is approximately 1.48 tesla (T).
To find the magnitude of the component of the magnetic field that is perpendicular to the wire, you can use the formula for the magnetic force on a current-carrying wire:
F = BILsinθ,
where F is the magnetic force, B is the magnitude of the magnetic field, I is the current, L is the length of the wire segment, and θ is the angle between the magnetic field and the wire.
In this case, we are given the values for F (1.0 N), I (4.5 A), and L (0.15 m). We need to find the magnitude of the magnetic field component, which is B.
Since the wire segment is straight and the force is perpendicular to the wire, the angle θ between the magnetic field and the wire is 90 degrees, which means sinθ is 1.
Using the formula, we can rearrange it to solve for B:
B = F / (ILsinθ).
Substituting the given values:
B = 1.0 N / (4.5 A * 0.15 m * 1).
Calculating:
B = 1.0 N / 0.675 A.m.
B ≈ 1.48 T.
Therefore, the magnitude of the component of the magnetic field that is perpendicular to the wire is approximately 1.48 T (tesla).