integral of : x^2 square root of (x-1)
Put x = y+1
Integral of x^2 sqrt(x-1) dx
= Integral of (y+1)^2 sqrt(y)dy =
Integral of [y^(5/2) + 2 y^(3/2) +
y^(1/2)]dy
= 2/7 y^(7/2) + 4/5 y^(5/2)
+ 2/3 y^(3/2)
Integral of x^2 sqrt(x-1) dx
= Integral of (y+1)^2 sqrt(y)dy =
Integral of [y^(5/2) + 2 y^(3/2) +
y^(1/2)]dy
= 2/7 y^(7/2) + 4/5 y^(5/2)
+ 2/3 y^(3/2)