A net charge of 47 mC passes through the cross-sectional area of a wire in 19.0 s.

(a) What is the current in the wire?
1 A
(b) How many electrons pass the cross-sectional area in 1.0 min?
2 . electrons

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To find the current in the wire, you can use Ohm's Law, which states that current (I) is equal to the charge (Q) passing through a point in the wire divided by the time (t) it takes for the charge to pass. The formula is:

I = Q / t

For part (a), we are given the charge Q = 47 mC and the time t = 19.0 s. To find the current, we can substitute these values into the formula:

I = 47 mC / 19.0 s

Before performing the calculation, we need to convert the charge into Coulombs (C) and the milliseconds (ms) into seconds (s). Let's do the conversions:

47 mC = 47 * 10^(-3) C (since 1 mC = 1 * 10^(-3) C)
19.0 s = 19.0 s

Now we can substitute the values into the formula and calculate the current:

I = (47 * 10^(-3) C) / 19.0 s
I ≈ 2.47 A

So, the current in the wire is approximately 2.47 A.

For part (b), we need to find the number of electrons passing through the cross-sectional area in 1.0 minute (60.0 s). To find this, we need to know the charge carried by a single electron and then divide the total charge (which we already know) by the charge per electron.

The charge carried by a single electron is approximately 1.602 x 10^(-19) C.

Number of electrons = (Total charge) / (Charge per electron)
Number of electrons = (47 mC) / (1.602 x 10^(-19) C)

Before performing the calculation, we need to convert the charge into Coulombs (C). Let's do the conversion:

47 mC = 47 * 10^(-3) C

Now we can substitute the values into the formula and calculate the number of electrons:

Number of electrons = (47 * 10^(-3) C) / (1.602 x 10^(-19) C)
Number of electrons ≈ 2.936 x 10^(19) electrons

So, approximately 2.936 x 10^(19) electrons pass the cross-sectional area in 1.0 minute.