What was the initial temperature of a sample pf silver that released 1207 joules when 150.0 grams of this metal were transferred to a cooler temperature of 60 degress Celsius?
1207 = mass Ag x specific heat x (Tfinal-Tintial)
Solve for Ti.
To determine the initial temperature of the silver sample, we can use the equation for heat transfer:
Q = mc∆T
Where:
Q = heat energy (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g·°C)
∆T = change in temperature (in °C)
In this case, we know:
Q = 1207 J
m = 150.0 g
∆T = final temperature - initial temperature = 60°C - initial temperature
The specific heat capacity for silver is approximately 0.24 J/g·°C.
We can rearrange the equation to solve for the initial temperature:
Q = mc∆T
∆T = Q / (mc)
∆T = 60°C - initial temperature
initial temperature = 60°C - ∆T
Substituting the given values:
∆T = 1207 J / (150.0 g * 0.24 J/g·°C)
∆T ≈ 3.36°C
Therefore, the initial temperature of the silver sample can be approximated as:
initial temperature = 60°C - 3.36°C
The initial temperature of the silver sample is approximately 56.64°C.