A monkey that weighs 270 newtons is hanging from a branch of a tree. What is the size and direction of the mobkeys force on the tree branch ? why? explain?
To determine the size and direction of the monkey's force on the tree branch, we need to understand the concept of Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.
In this scenario, the action is the monkey's weight pulling downwards due to gravity with a force of 270 newtons. According to Newton's third law, the reaction force will be equal in size but opposite in direction to the action force. Therefore, the monkey's force on the tree branch will also be 270 newtons, but in the upward direction.
To calculate the monkey's force on the tree branch, we can simply use the weight of the monkey, as weight is the force acting on an object due to gravity. Weight can be calculated by multiplying the mass of the object by the acceleration due to gravity (which is approximately 9.8 m/s^2 on Earth).
If we assume that the acceleration due to gravity is 9.8 m/s^2, we can use the formula:
Weight = mass * acceleration due to gravity
Since the weight is given as 270 newtons, we can rearrange the formula to solve for the mass of the monkey. Rearranging the formula, we have:
mass = weight / acceleration due to gravity
mass = 270 N / 9.8 m/s^2
mass ≈ 27.55 kg
So, we can determine that the mass of the monkey is approximately 27.55 kg.
Therefore, the monkey's force on the tree branch is 270 newtons, directed upwards, as it is the reaction force to counteract the monkey's weight pulling downwards due to gravity.