a model of a house is drawn using a scale of 3in=15ft. what is the length of the actual house if the model has a length of 15in
Cross multiply and solve for x
3/15 = 15/x
so is it x=225in
No.
Cross multiply:
15 * 15 = 3x
225 = 3x
75 = x
The actual house is 75 feet long.
To find the length of the actual house, we can use the scale factor provided in the problem. The scale is 3in = 15ft. This means that for every 3 inches on the model, it represents 15 feet in reality.
Given that the length of the model is 15 inches, we can set up a proportion to find the length of the actual house.
Let's call the length of the actual house "x."
Proportion:
(model length) / (actual length) = (scale on the model) / (scale in reality)
Plugging in the values:
15in / x = 3in / 15ft
To solve for x, we need to get rid of the units. Since both sides of the equation have inches and feet, we need to convert one set of units to match the other.
1ft = 12in, so 15ft = 15ft * 12in/1ft = 180in.
Now our proportion is:
15in / x = 3in / 180in
To solve for x, we cross-multiply:
15in * 180in = 3in * x
2700in^2 = 3in * x
Now, divide both sides of the equation by 3in:
2700in^2 / 3in = x
Simplifying the units:
900in = x
Therefore, the length of the actual house is 900 inches.