Tickets on the ferris wheel cost .50 cents. At least how many tickets were sold? There are 36 cars on the ferris wheel that holds 60 people per car. Suppose every ticket holder rode for two turns of the wheel. At least how many turns did the wheel have to make? I think it's two, and that the cost of the tickets doesn't matter, but is this a trick question? Please help me!
Do you realize that this -- ".50 cents" -- means half a cent?? Are you sure you want to compute your problem with half-cent tickets??
Those are awfully big cars to hold 60 people each.
Do you need to consider the turning the wheel takes as it is loading and unloading? In other words, in terms of loading, one car would be filled, the wheel would proceed 1/36 to the next car, etc…. Once loaded everyone would have two turns of the wheel. Then they have to unload in a similar way.
I hope this helps.
Thanks PsyDAG. This was the very first ferris Wheel so that's why it was so big and held a lot of people. I wasn't given any other information.
To find the minimum number of tickets sold, we need to consider the maximum number of people the ferris wheel can hold since each car has a capacity of 60 people. The total number of people the ferris wheel can accommodate at once is 36 cars * 60 people/car = 2160 people.
Since each person rides for two turns of the wheel, we need to divide the total number of people by 2 to find the minimum number of turns the wheel has to make. Therefore, the ferris wheel needs to make at least 2160 people / 2 = 1080 turns.
The cost of the tickets doesn't impact the number of turns the wheel has to make. It only affects the revenue generated from the ticket sales.
So, to answer your question, the ferris wheel has to make at least 1080 turns, assuming every ticket holder rides for two turns.