John has two part time jobs. He works no more than 40 hours per week. He earns $6 per hour from the first job and $8 per hour from the second job. To cover his expenses, he needs to earn at lease $210 per week. Which of the following system of linear inequalities shows the number of hours he can work on each job? Let x be the number of hours he can work per week in the first job and y be the number of hours of work per week in the second job.

x+y <= 40

6x+8y >= 210

jessie saves $6 each week.in how many weeks will she have saved at least $50?

To solve this problem, we can set up a system of linear inequalities based on the given conditions.

Let's first determine the number of hours John can work on each job. We'll call the number of hours he can work in the first job "x" and the number of hours he can work in the second job "y".

From the given information, we know the following:
- John works no more than 40 hours per week, so we can write the inequality: x + y ≤ 40

We also know that John earns $6 per hour from the first job and $8 per hour from the second job. To cover his expenses, he needs to earn at least $210 per week. We can write this information as an inequality as well:
- 6x + 8y ≥ 210

Putting both inequalities together, we have the system of linear inequalities:

x + y ≤ 40
6x + 8y ≥ 210

So, the correct system of linear inequalities showing the number of hours John can work on each job is:
x + y ≤ 40
6x + 8y ≥ 210