How much charge passes through a cross-sectional area of a copper wire in 0.8 s if I = 3.5 A?
1 C
is 2.8 right?
To find the amount of charge passing through a cross-sectional area of a copper wire, you can use the equation:
Q = I * t
Where:
Q is the amount of charge passing through the cross-sectional area,
I is the current passing through the wire, and
t is the time for which the current flows.
In this case, the current (I) is given as 3.5 A, and the time (t) is given as 0.8 s.
Now, substitute these values into the equation:
Q = 3.5 A * 0.8 s
Q = 2.8 C
Therefore, the amount of charge passing through the cross-sectional area of the copper wire in 0.8 s is 2.8 Coulombs (C).