Write the double-replacement reaction of HgCl2 reacting with Na2CO3.
==>HgCO3 + 2NaCl
I need information about why does this reaction occurs...
To write the double-replacement reaction between HgCl2 and Na2CO3, we need to determine the products that form when the two compounds react.
Step 1: Write the formulas of the reactants.
HgCl2 (Mercury(II) chloride)
Na2CO3 (Sodium carbonate)
Step 2: Identify the cations (positively charged ions) and anions (negatively charged ions) in each compound.
HgCl2: Mercury(II) cation (Hg2+) and chloride anion (Cl-)
Na2CO3: Sodium cation (Na+) and carbonate anion (CO3^2-)
Step 3: Determine the possible combination of the cations and anions.
In a double-replacement reaction, the cations and anions exchange partners to form new compounds.
Hg2+ combines with CO3^2- to form HgCO3 (Mercury(II) carbonate).
Na+ combines with Cl- to form NaCl (Sodium chloride).
Step 4: Write the balanced chemical equation.
HgCl2 + Na2CO3 -> HgCO3 + 2NaCl
Therefore, the double-replacement reaction between HgCl2 and Na2CO3 is:
HgCl2 + Na2CO3 -> HgCO3 + 2NaCl