Classify the following 3 acids in order of increasing acidity:
Acid 1:Ka = 8 x 10-6
Acid 2:Ka = 6 x 10-4
Acid 3:Ka = 9 x 10-11
To determine the order of increasing acidity for the given acids, we need to compare their acid dissociation constants (Ka). The higher the Ka value, the stronger the acid.
The given acids can be arranged in increasing order of acidity as follows:
Acid 3: Ka = 9 x 10-11
Acid 1: Ka = 8 x 10-6
Acid 2: Ka = 6 x 10-4
To clarify, let's discuss how to compare the acidity using the Ka values:
1. Identify the Ka values for each acid:
Acid 1: Ka = 8 x 10-6
Acid 2: Ka = 6 x 10-4
Acid 3: Ka = 9 x 10-11
2. Compare the Ka values:
Acid 3 (Ka = 9 x 10-11) has the smallest Ka value, making it the weakest acid among the three.
Acid 2 (Ka = 6 x 10-4) has a larger Ka value than Acid 3 but is still weaker than Acid 1.
Acid 1 (Ka = 8 x 10-6) has the highest Ka value, making it the strongest acid among the three.
Therefore, the order of increasing acidity is Acid 3 < Acid 2 < Acid 1.
To classify the three acids in order of increasing acidity, we need to compare their acid dissociation constants (Ka). The smaller the value of Ka, the weaker the acid and the less acidic it is.
Let's compare the Ka values of the three acids:
Acid 1: Ka = 8 x 10^-6
Acid 2: Ka = 6 x 10^-4
Acid 3: Ka = 9 x 10^-11
Now, let's compare the values:
Acid 3 has the smallest Ka value (9 x 10^-11), so it is the weakest acid and the least acidic.
Acid 1 has a larger Ka value (8 x 10^-6), so it is stronger than acid 3 but weaker than acid 2.
Acid 2 has the largest Ka value (6 x 10^-4), so it is the strongest acid and the most acidic.
Therefore, the acids can be classified in increasing acidity as follows:
Acid 3 < Acid 1 < Acid 2