hello I need help to do this exercise

Consider the function f (x) = (16 x + 33) / (x +3)
1) Determine its domain Df
2) Solve the equation f (x) = 14
3) Show that for all x in Df: f (x) - 15 = (x-12) / (x +3)
4) deduct the resolution of the inequality f (x)> 15.

Thanks for your help.

1 )

The domain of a function is the set of all possible input values , which allows the function formula to work.

The denominator of any fraction cannot have the value zero.

I this case :

x + 3

must be different of zero

x different of - 3

Domain:

( - infinity , - 3 ) U ( - 3 , infinity )

OR

all values of x different of - 3

2 )

( 16 x + 33 ) / ( x + 3 ) = 14 Multiply both sides by ( x + 3 )

16 x + 33 = 14 * ( x + 3 )

16 x + 33 = 14 x + 14 * 3

16 x + 33 = 14 x + 42

16 x - 14 x = 42 - 33

2 x = 9 Divide both sides by 2

x = 9 / 2

3 )

f ( x ) - 15 =

( 16 x + 33 ) / ( x + 3 ) - 15 * ( x + 3 ) / ( x + 3 ) =

( 16 x + 33 - 15 x - 15 * 3 ) / ( x + 3 ) =

( x + 33 - 45 ) / ( x + 3 ) =

( x - 12 ) / ( x + 3 )

4 )

( 16 x + 33 ) / ( x + 3 ) > 15
Multiply both sides by ( x + 3 )

16 x + 33 > 15 * ( x + 3 )

16 x + 33 > 15 x + 15 * 3

16 x + 33 > 15 x + 45

16 x - 15 x > 45 - 33

x > 12

Thanks :)

Of course! I can help you with that.

1) To determine the domain of the function f(x), we need to find all the values of x that make the function defined. The function f(x) has a fraction with a denominator of (x+3). Since dividing by zero is not defined, we need to make sure that x+3 is not equal to zero.

To find the domain, we set the denominator equal to zero and solve for x:
x + 3 = 0
x = -3

So, the function f(x) is defined for all real numbers except x = -3. Therefore, the domain of f(x) is all real numbers except -3.

2) To solve the equation f(x) = 14, we set the function equal to 14 and solve for x:
(16x + 33) / (x + 3) = 14

To solve this equation, we can first cross-multiply to get rid of the fraction:
(16x + 33) = 14(x + 3)

Now we can distribute and solve for x:
16x + 33 = 14x + 42
2x = 9
x = 9/2 or x = 4.5

So the solutions to the equation f(x) = 14 are x = 9/2 or x = 4.5.

3) To show that for all x in Df: f(x) - 15 = (x-12) / (x + 3), we can substitute the function f(x) into the equation and simplify:

f(x) = (16x + 33) / (x + 3)

f(x) - 15 = ((16x + 33) / (x + 3)) - 15

To simplify further, we can find a common denominator and combine the fractions:
f(x) - 15 = ((16x + 33) - 15(x + 3)) / (x + 3)

Expanding and simplifying the numerator:
f(x) - 15 = (16x + 33 - 15x - 45) / (x + 3)
f(x) - 15 = (x -12) / (x + 3)

Therefore, for all x in Df, f(x) - 15 = (x - 12) / (x + 3).

4) To deduce the resolution of the inequality f(x) > 15, we can start by finding the critical points where f(x) equals or crosses the value of 15. We can set the function equal to 15 and solve for x:

(16x + 33) / (x + 3) = 15

To solve this equation, we can cross-multiply and simplify:
16x + 33 = 15(x + 3)
16x + 33 = 15x + 45
x = 12

So, x = 12 is the critical point where f(x) = 15.

To resolve the inequality f(x) > 15, we need to consider two cases:
- When x < -3: Since x is less than -3, the denominator (x+3) is negative, which means the whole fraction is negative. Hence, f(x) will always be less than 15. Therefore, there is no solution in this case.
- When x > -3: Since x is greater than -3, the denominator (x+3) is positive, which means the whole fraction is positive. Hence, f(x) can be greater than 15. Therefore, the solution to the inequality f(x) > 15 is the set of all x values greater than -3.

To summarize, the solution to the inequality f(x) > 15 is x > -3.