You work with the following system:

2X(g) <--> Y(g)

At, equilibrium, [Y]=3[X]. If K=10, calculate the [Y] at equilibrium.

K = 10 = (Y)/(X)^2 = 3X/(X)^2 = 3/X

10 = 3/X; X = 3/10 = 0.30

To solve this question, we can use the formula for equilibrium constant (K):

K = [Y]^y / [X]^x

Given that K = 10 and [Y] = 3[X], we can substitute these values into the formula:

10 = (3[X])^y / [X]^x

To simplify this equation, we need to determine the values of x and y. Looking at the balanced equation, we have:

2X(g) <--> Y(g)

This means that the coefficients in front of X and Y are 2 and 1, respectively. Therefore, x = 2 and y = 1.

Now, we can substitute these values into the equation:

10 = (3[X])^1 / [X]^2

Simplifying further, we have:

10 = 3[X] / [X]^2

To eliminate the fraction, we multiply both sides of the equation by [X]^2:

10[X]^2 = 3[X]

Now, we can rearrange the equation:

10[X]^2 - 3[X] = 0

Factoring out an [X], we get:

[X] * (10[X] - 3) = 0

From this equation, we have two possible solutions:

1) [X] = 0

2) 10[X] - 3 = 0

Solving the second equation for [X], we get:

10[X] = 3

[X] = 3/10

Now that we have the value of [X], we can calculate the value of [Y] using the given relationship:

[Y] = 3[X] = 3 * (3/10) = 9/10

Therefore, the [Y] at equilibrium is 9/10.

To calculate the concentration of Y at equilibrium, we can use the equilibrium constant (K) expression and the given information.

The equilibrium constant expression for the reaction is:

K = ([Y]/[X]^2)

Given that [Y] = 3[X] at equilibrium, we can substitute this into the expression:

K = ([Y]/[X]^2) = (3[X])/[X]^2 = 3/[X]

Since the equilibrium constant (K) value is given as 10, we can set up the following equation:

10 = 3/[X]

To solve for [X], we can rearrange the equation as follows:

[X] = 3/10

Now that we have the concentration of X at equilibrium, we can use the given relationship between [X] and [Y] to find the concentration of Y. Since [Y] = 3[X], we can substitute the value of [X] we just calculated:

[Y] = 3 * (3/10) = 9/10

Therefore, the concentration of Y at equilibrium is 9/10.