For each reaction,which ion in the precipitate was responsible for the color
1-reaction of Sodium Hydroxide and Copper(II)Sulfate
2-reaction of Sodium Sulfate and Barium Chloride.
3-reaction of Sodium Hydroxide and Iron(III)Sulfate.
4-reaction of Sodium Hydroxide and Nickel(II)chloride.
5-reaction of Potassium Iodide and lead (II)Nitrate.
6-reaction of Sodium Hydroxide and Iron(II)Sulfate.
Cu, Ba, Fe, Ni, I, Fe
1. The precipitate formed in the reaction between Sodium Hydroxide and Copper(II) Sulfate is Copper(II) Hydroxide (Cu(OH)2). The Cu(II) ion is responsible for the blue color of the precipitate.
2. The precipitate formed in the reaction between Sodium Sulfate and Barium Chloride is Barium Sulfate (BaSO4). The Ba2+ ion is responsible for the white color of the precipitate.
3. The precipitate formed in the reaction between Sodium Hydroxide and Iron(III) Sulfate is Iron(III) Hydroxide (Fe(OH)3). The Fe3+ ion is responsible for the reddish-brown color of the precipitate.
4. The precipitate formed in the reaction between Sodium Hydroxide and Nickel(II) Chloride is Nickel(II) Hydroxide (Ni(OH)2). The Ni2+ ion is responsible for the green color of the precipitate.
5. The precipitate formed in the reaction between Potassium Iodide and Lead(II) Nitrate is Lead(II) Iodide (PbI2). The Pb2+ ion is responsible for the yellow color of the precipitate.
6. The precipitate formed in the reaction between Sodium Hydroxide and Iron(II) Sulfate is Iron(II) Hydroxide (Fe(OH)2). The Fe2+ ion is responsible for the greenish precipitate.
To determine which ion in the precipitate is responsible for the color in each reaction, we need to know the common precipitation reactions for the ions and their corresponding colors.
1. Reaction of Sodium Hydroxide and Copper(II) Sulfate:
In this reaction, the copper(II) ion (Cu2+) and the hydroxide ion (OH-) combine to form copper(II) hydroxide (Cu(OH)2), which is a blue precipitate. Therefore, it is the copper(II) ion (Cu2+) responsible for the blue color.
2. Reaction of Sodium Sulfate and Barium Chloride:
When sodium sulfate (Na2SO4) and barium chloride (BaCl2) react, barium sulfate (BaSO4) is formed as a white precipitate. Hence, it is the sulfate ion (SO42-) responsible for the white color.
3. Reaction of Sodium Hydroxide and Iron(III) Sulfate:
The reaction between sodium hydroxide (NaOH) and iron(III) sulfate (Fe2(SO4)3) forms iron(III) hydroxide (Fe(OH)3) as a rusty/brown precipitate. Thus, it is the iron(III) ion (Fe3+) responsible for the brown color.
4. Reaction of Sodium Hydroxide and Nickel(II) Chloride:
When sodium hydroxide (NaOH) reacts with nickel(II) chloride (NiCl2), nickel(II) hydroxide (Ni(OH)2) is formed as a green precipitate. Therefore, it is the nickel(II) ion (Ni2+) responsible for the green color.
5. Reaction of Potassium Iodide and Lead(II) Nitrate:
In this reaction, potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2) form lead(II) iodide (PbI2) as a yellow precipitate. Thus, it is the lead(II) ion (Pb2+) responsible for the yellow color.
6. Reaction of Sodium Hydroxide and Iron(II) Sulfate:
When sodium hydroxide (NaOH) reacts with iron(II) sulfate (FeSO4), iron(II) hydroxide (Fe(OH)2) is formed. However, iron(II) hydroxide is a green gelatinous precipitate that quickly oxidizes to form brown rust, which is iron(III) hydroxide (Fe(OH)3). Therefore, it is the iron(III) ion (Fe3+) responsible for the brown color.
In summary:
1. Copper(II) sulfate - Cu2+ (responsible for the blue color)
2. Barium chloride - SO42- (responsible for the white color)
3. Iron(III) sulfate - Fe3+ (responsible for the brown color)
4. Nickel(II) chloride - Ni2+ (responsible for the green color)
5. Lead(II) nitrate - Pb2+ (responsible for the yellow color)
6. Iron(II) sulfate - Fe3+ (responsible for the brown color)