What volume of a 2.5 M stock solution of acetic acid (HC¿HÀO¿) is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution?
To find out what volume of a 2.5 M stock solution of acetic acid is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution, we can use the equation:
M1V1 = M2V2
Where:
M1 = concentration of the stock solution (2.5 M)
V1 = volume of the stock solution needed
M2 = concentration of the desired solution (0.50 M)
V2 = final volume of the desired solution (100.0 mL)
Substituting the given values into the equation, we can solve for V1:
(2.5 M)(V1) = (0.50 M)(100.0 mL)
Dividing both sides of the equation by 2.5 M:
V1 = (0.50 M)(100.0 mL) / 2.5 M
Simplifying:
V1 = (0.50/2.5)(100.0)
V1 = (0.20)(100.0)
V1 = 20.0 mL
Therefore, in order to prepare 100.0 mL of a 0.50 M acetic acid solution, 20.0 mL of the 2.5 M stock solution of acetic acid is required.
To determine the volume of a 2.5 M stock solution of acetic acid required to prepare 100.0 milliliters (mL) of a 0.50 M acetic acid solution, we can use the equation:
(C₁)(V₁) = (C₂)(V₂)
where:
C₁ = concentration of the stock solution (2.5 M)
V₁ = volume of the stock solution (to be determined)
C₂ = concentration of the desired solution (0.50 M)
V₂ = volume of the desired solution (100.0 mL)
Rearranging the equation, we have:
V₁ = (C₂)(V₂) / C₁
Plugging in the values:
V₁ = (0.50 M)(100.0 mL) / 2.5 M
Simplifying:
V₁ = 20 mL
Therefore, you would need to take 20 mL of the 2.5 M stock solution of acetic acid and then dilute it to a final volume of 100.0 mL to prepare a 0.50 M acetic acid solution.