An aqueous solution of volume 7 dm3 is obtained by dissolving 5.5 kg of C12H22O11 in enough water. express the concentration in mol/L and mol/Kg
To find the concentration of the solution in mol/L, we need to determine the number of moles of C12H22O11 dissolved in the solution.
First, let's calculate the molar mass of C12H22O11 (sucrose):
C: 12.01 g/mol
H: 1.01 g/mol
O: 16.00 g/mol
Molar mass of C12H22O11:
(12.01 * 12) + (1.01 * 22) + (16.00 * 11) = 342.34 g/mol
Next, we convert the mass of C12H22O11 (5.5 kg) to grams:
5.5 kg * 1000 g/kg = 5500 g
Now, we can calculate the number of moles of C12H22O11 using the formula:
moles = mass / molar mass
moles = 5500 g / 342.34 g/mol ≈ 16.06 mol
The volume of the solution is given as 7 dm3, which is equal to 7 L.
Concentration (mol/L) = moles / volume
Concentration (mol/L) = 16.06 mol / 7 L ≈ 2.29 mol/L
To convert the concentration to mol/kg, we need to consider the mass of the solvent (water). Since water has a density of 1 g/mL or 1 kg/L, the mass of water is equal to its volume.
Mass of water = Volume of water = 7 kg
Concentration (mol/kg) = moles / mass of solvent
Concentration (mol/kg) = 16.06 mol / 7 kg ≈ 2.29 mol/kg
Therefore, the concentration of the aqueous solution is approximately 2.29 mol/L and 2.29 mol/kg.