An indoor running track has the dimensions shown. The ends of the track are semicircles. If the track is to be resurfaced, how many square feet of material will be required? The semicircle is listed at 34 ft., the straightaway at 80 ft., and individual lane width is 5ft. Please Help!

inside or outside of the circle is 34? How many lanes?

you will end up with a circle of some width, and a rectangle.

If the radii of the circle are R and r, the its area will be pi(R^2-r^2)

the rectangle you can prolly figure out.

Come back with what you figure out, and show where you get stuck, if you do. But be sure to provide complete information. There are no diagrams here.

To find the total area of the indoor running track, we need to calculate the areas of the semicircles at both ends and the rectangle in between.

First, let's calculate the area of each end's semicircle.

The formula for the area of a circle is A = πr², but since we only have a semicircle, we need to divide the result by 2. Given that the semicircle has a listed radius of 34 ft, we can calculate its area as follows:

Area of semicircle = (π * r²) / 2 = (π * 34²) / 2

Next, we need to calculate the area of the rectangle in between the semicircles. The straightaway section has a length of 80 ft and a width equal to the lane width. Since there is only one lane mentioned, the width of the rectangle can be considered as 5 ft.

Area of rectangle = length * width = 80 ft * 5 ft

Now, we can calculate the total area of the running track by summing the areas of the semicircles and rectangle.

Total area = 2 * (Area of semicircle) + Area of rectangle

Substituting the calculated values, we get:

Total area = 2 * ((π * 34²) / 2) + (80 ft * 5 ft)

Simplifying further:

Total area = π * 34² + 400 ft²
Total area ≈ 3612.57 ft²

Therefore, approximately 3612.57 square feet of material will be required to resurface the indoor running track.