Plz give me some idea that how can i do this program.
Write a program that uses a 20x20 board, initialised to a given pattern, to play the game Conway's life . After each turn print out the board pattern using a . for a dead square and a * for a live square. Squares off the board are considered permanently dead.
thanku
To write a program that plays Conway's Game of Life on a 20x20 board, you can follow these steps:
1. Initialize the board: Start by creating a 20x20 board and initializing it with a given pattern. You can represent the board using a 2-dimensional array.
2. Implement the rules of the game: Conway's Game of Life has three rules:
- Any live cell with fewer than two live neighbors dies (underpopulation).
- Any live cell with two or three live neighbors continues to live.
- Any live cell with more than three live neighbors dies (overpopulation).
- Any dead cell with exactly three live neighbors becomes a live cell (reproduction).
For each turn, iterate over all the cells on the board, and apply these rules to determine the state of each cell in the next generation.
3. Print the board: After each turn, print out the board pattern. Use a "." for a dead square and a "*" for a live square. Keep in mind that squares off the board are considered permanently dead.
Here's a simple example in Python:
```python
import random
# Initialize the board
board = [[random.choice(['.', '*']) for _ in range(20)] for _ in range(20)]
# Print the initial board
for row in board:
print(' '.join(row))
# Function to count live neighbors
def count_live_neighbors(board, row, col):
count = 0
for i in range(max(0, row-1), min(row+2, len(board))):
for j in range(max(0, col-1), min(col+2, len(board[0]))):
if (i, j) != (row, col) and board[i][j] == '*':
count += 1
return count
# Function to update the board for the next generation
def update_board(board):
new_board = [['.' for _ in range(20)] for _ in range(20)]
for row in range(len(board)):
for col in range(len(board[0])):
live_neighbors = count_live_neighbors(board, row, col)
if board[row][col] == '*':
if live_neighbors < 2 or live_neighbors > 3:
new_board[row][col] = '.'
else:
new_board[row][col] = '*'
else:
if live_neighbors == 3:
new_board[row][col] = '*'
return new_board
# Run the game for a specific number of turns
num_of_turns = 10
for _ in range(num_of_turns):
board = update_board(board)
print('---')
for row in board:
print(' '.join(row))
```
This example initializes the board randomly and runs the game for 10 turns. You can modify the code to initialize the board with a specific pattern and adjust the number of turns according to your requirements.