An ideal transformer has 50 turns in its primary coil and 250 turns in its secondary coil. 12 V is connected to the primary.
a)find the voltage across the secondary coil.
b) find the current in a 10-ohms device connected to the secondary.
c) find the power supplied to the primary.
The turns ratio N2/N1 equals the factor by which the voltage increases: V2/V1.
V2/R is the secondary current
V2*I2 is the secondary power, and it equals the primary power.
secondary coil 60v
Just trying
To find the voltage across the secondary coil (Vs), you can use the turns ratio between the primary and secondary coils. The turns ratio is given by:
Turns ratio = Ns / Np
Where Ns is the number of turns in the secondary coil and Np is the number of turns in the primary coil.
In this case, Ns = 250 and Np = 50. So the turns ratio is:
Turns ratio = 250 / 50 = 5
The voltage across the secondary coil (Vs) can be found by multiplying the turns ratio by the voltage across the primary coil (Vp). In this case, Vp = 12 V. Therefore:
Vs = Turns ratio * Vp
= 5 * 12 V
= 60 V
So the voltage across the secondary coil is 60 V.
To find the current in a 10-ohm device connected to the secondary coil, you can use the relationship between voltage (Vs) and current (Is) in a circuit, which can be given by Ohm's Law:
Is = Vs / Rs
Where Vs is the voltage across the secondary coil and Rs is the resistance of the 10-ohm device.
Using the value of Vs from the previous calculation (Vs = 60 V) and the resistance of the device (Rs = 10 ohms), we can calculate the current:
Is = 60 V / 10 ohms
= 6 A
So the current flowing through the 10-ohm device connected to the secondary coil is 6 A.
To find the power supplied to the primary coil, you can use the relationship between voltage (Vp) and current (Ip) in a circuit, which can also be given by Ohm's Law:
Pp = Vp * Ip
Where Vp is the voltage across the primary coil and Ip is the current flowing through the primary coil.
In this case, Vp = 12 V and Ip is not given. However, we can calculate Ip using the turns ratio and the current in the secondary coil (Is). The turns ratio is 5, and Is was calculated to be 6 A.
Since the transformer is an ideal transformer, the power in the secondary coil is equal to the power in the primary coil. Therefore:
Ps = Pp
And since power is the product of voltage and current, we have:
Vs * Is = Vp * Ip
Rearranging the equation to solve for Ip:
Ip = (Vs * Is) / Vp
= (60 V * 6 A) / 12 V
= 30 A
So the current flowing through the primary coil is 30 A.
Finally, we can calculate the power supplied to the primary coil:
Pp = Vp * Ip
= 12 V * 30 A
= 360 W
So the power supplied to the primary coil is 360 W.
To summarize:
a) The voltage across the secondary coil is 60 V.
b) The current in the 10-ohm device connected to the secondary coil is 6 A.
c) The power supplied to the primary coil is 360 W.
vs=VP*ns
50vs=250*12
50vs=3000รท50
vs=60v