advanced functions grd 12

im not sure wheer to start and how to do solve this problem
solve: cosX(2sinX-3^1/2)=0 ,0<(or equal to)X<(or equal to)2(pie sign)

asked by kerry
  1. I read that as
    cosx(2sinx - √3) = 0 , 0 ≤ x ≤ 2π

    since it is already factored we can say
    cosx=0 OR sinx = √3/2

    if cosx = 0
    x = π/2 or x = 3π/2 , (90° or 270°)

    if sinx = √3/2
    then x must be in quadrants I or II
    x = π/3 or x = 2π/3 , (60° or 120°)

    posted by Reiny
  2. i didn't know how to put the root in so i converted it by adding in the 1/2 exponent! thank you :)

    posted by kerry

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