What mass of sodium oxide could be made from 1,15 grams of sodium
4Na + 02 = 2Na2O
Considering Na is the limiting reagent..
1.15g Na x 1molNa/23g x 2molNa2O/4molNa x 1molNa2O/62g = grams of Na2O
To determine the mass of sodium oxide that can be produced from 1.15 grams of sodium, we need to know the balanced chemical equation for the reaction between sodium and oxygen. The balanced equation for the formation of sodium oxide (Na2O) is:
4Na + O2 -> 2Na2O
From the equation, we can see that 4 moles of sodium react with 1 mole of oxygen to produce 2 moles of sodium oxide. Now we can proceed with the steps to calculate the mass:
Step 1: Convert the given mass of sodium (1.15 grams) to moles.
To do this, we will need the molar mass of sodium, which is 22.99 g/mol.
Number of moles of sodium = Mass of sodium / molar mass of sodium
Number of moles of sodium = 1.15 g / 22.99 g/mol
Step 2: Use the mole ratio from the balanced equation to find the number of moles of sodium oxide.
From the balanced equation, 4 moles of sodium react to form 2 moles of sodium oxide.
Number of moles of sodium oxide = (Number of moles of sodium) / (4 moles of sodium / 2 moles of sodium oxide)
Step 3: Convert the moles of sodium oxide to grams.
To do this, we will need the molar mass of sodium oxide, which is 61.98 g/mol.
Mass of sodium oxide = Number of moles of sodium oxide * molar mass of sodium oxide
Now, let's calculate the mass of sodium oxide:
Number of moles of sodium = 1.15 g / 22.99 g/mol ≈ 0.05 moles of sodium
Number of moles of sodium oxide = (0.05 moles of sodium) / (4 moles of sodium / 2 moles of sodium oxide) ≈ 0.025 moles of sodium oxide
Mass of sodium oxide = 0.025 moles of sodium oxide * 61.98 g/mol ≈ 1.55 grams of sodium oxide
Therefore, approximately 1.55 grams of sodium oxide can be made from 1.15 grams of sodium.