What is the Net Ionic Reaction for NaOH(aq) + H2SO4(aq)-->

To determine the net ionic reaction for NaOH(aq) + H2SO4(aq), we first need to write out the balanced molecular equation:

NaOH(aq) + H2SO4(aq) -> Na2SO4(aq) + H2O(l)

Next, we can split the soluble ionic compounds into their respective ions:

NaOH(aq) -> Na+(aq) + OH-(aq)
H2SO4(aq) -> 2H+(aq) + SO4^(2-)(aq)
Na2SO4(aq) -> 2Na+(aq) + SO4^(2-)(aq)

Now, we can identify the spectator ions, which are the ions that appear on both sides of the equation. These ions do not participate in the reaction:

Na+(aq) and SO4^(2-)(aq)

The net ionic reaction only includes the reactant and product ions that participate in the reaction, excluding the spectator ions. The net ionic reaction for NaOH(aq) + H2SO4(aq) is:

2H+(aq) + 2OH-(aq) -> 2H2O(l)

To determine the net ionic reaction for the given reaction, we need to first write the balanced molecular equation and then write the complete ionic equation. From there, we can isolate the spectator ions and write the net ionic equation.

Step 1: Write the balanced molecular equation:
NaOH(aq) + H2SO4(aq) --> Na2SO4(aq) + H2O(l)

Step 2: Write the complete ionic equation:
Na+(aq) + OH-(aq) + H+(aq) + SO4^2-(aq) --> 2Na+(aq) + SO4^2-(aq) + H2O(l)

In the complete ionic equation, all aqueous ionic compounds are split into their respective ions.

Step 3: Identify spectator ions:
In this reaction, the sodium ions (Na+) and sulfate ions (SO4^2-) are present on both sides of the equation and do not participate in the reaction.

Step 4: Write the net ionic equation:
OH-(aq) + H+(aq) --> H2O(l)

The net ionic equation eliminates the spectator ions to show only the species that are directly involved in the reaction. In this case, hydroxide ion (OH-) and hydrogen ion (H+) react to form water (H2O).

Therefore, the net ionic reaction for NaOH(aq) + H2SO4(aq) is OH-(aq) + H+(aq) --> H2O(l).

2OH^- + 2H^+ ==> 2H2O