What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.82?
well noone answered it and so i reposst it. thank you for your responnse but the last message was not needed.
The car moves forward by the reaction force from the ground, produced due to friction between tires and road. According to the Newton’s 3rd law
F12 = F21
F(net)max = F(friction)max
m•a = k• m•g
a = k• g = 0.82•9.8 = 8.04 m/s^2
To determine the maximum acceleration a car can undergo, we first need to calculate the maximum possible static frictional force acting on the tires. This force can be found using the equation:
Maximum static frictional force = coefficient of static friction * normal force
The normal force refers to the force exerted by the ground on the car, which is equal to the car's weight (mg) in the absence of any vertical acceleration.
To find the maximum acceleration, we need to consider Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:
Net force = mass * acceleration
In this case, the maximum static frictional force acts as the net force.
Rearranging the equation, we get:
Acceleration = maximum static frictional force / mass
Now, we have all the necessary information to calculate the maximum acceleration of the car.
Please provide the mass of the car so that we can proceed with the calculation.
1. Fnet=ma=Fs
Fnet=ma=usFn
Fnet=ma=usmg
mass cancels
a=usg
Please stop reposting your question