A 10 g mass of krypton occupies 15.0L at a pressure of 210 kPa. Find the volume of the krypton when the pressure is increased to 790kPa.
Thanks
P1V1 = P2V2
To find the volume of krypton when the pressure is increased to 790 kPa, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature:
P1 x V1 = P2 x V2
Where:
P1 = initial pressure (210 kPa)
V1 = initial volume (15.0 L)
P2 = final pressure (790 kPa)
V2 = final volume (unknown, to be solved)
We can rearrange the equation to solve for V2:
V2 = (P1 x V1) / P2
Plugging in the given values:
V2 = (210 kPa x 15.0 L) / 790 kPa
Simplifying the equation:
V2 = 3.97 L
Therefore, the volume of krypton when the pressure is increased to 790 kPa is approximately 3.97 L.