Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Trigonometry
Finding angle using trigonometric equation
if tanx = 3 find x (3sf)
-
8
1 answer
tanx = 3
X = 71.57 Deg.
You can
ask a new question
or
answer this question
.
Related Questions
How do I solve this?
tan^2x= 2tanxsinx My work so far: tan^2x - 2tanxsinx=0 tanx(tanx - 2sinx)=0 Then the solutions are: TanX=0
For x≠0, the slope of the tangent to y=xcosx equals zero whenever:
(a) tanx=-x (b) tanx=1/x (c) sinx=x (d) cosx=x Please help.
1. (sec^2x-6tanx+7/sec^2x-5)=(tanx-4/tanx+2)
2. (sin^3A+cos^3A/sinA+cosA)=1-sinAcosA 3. csc^6x-cot^6x+1+3csc^2xcot^2x please help
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.
I don't know what i'm supposed to
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.
I don't know what i'm supposed to
I can't find the integral for
(tanx)^(6)*(secx)^(2) I tried splitting up tanx into (tanx)^2*(tanx)^4 and let the latter equal
2tan^2x-tanx-1=0
0<x<2pi •MATH - Steve, Thursday, July 18, 2013 at 11:48am (2tanx+1)(tanx-1) = 0 tanx = -1/2 or 1 ... Recall in
Did I do this problem right?
Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'=
For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
Derivative of y=sec(tanx)?
I don't get how it is secxsecx*secxtanx*tanxtanx. Where does an extra tanx come from? Derivative of
