How many grams of lithium metal would be produced if 0.500g of magnesium was added to a solution of lithium chloride?
None. Mg will not displace Li^+ from LiCl.
To determine how many grams of lithium metal would be produced, we need to consider the reaction between magnesium and lithium chloride. The balanced chemical equation for the reaction is:
2 Mg + 2 LiCl → 2 MgCl₂ + 2 Li
From the equation, we can see that 2 moles of magnesium react with 2 moles of lithium chloride to produce 2 moles of magnesium chloride and 2 moles of lithium.
To find the number of moles of magnesium in 0.500g, we need to divide the mass by the molar mass of magnesium. The molar mass of magnesium (Mg) is approximately 24.31 g/mol.
Number of moles of magnesium:
0.500g / 24.31 g/mol ≈ 0.0206 mol
Since the reaction is in a 1:1 ratio for magnesium and lithium, the number of moles of lithium produced will also be 0.0206 mol.
To find the mass of lithium produced, we multiply the number of moles by the molar mass of lithium. The molar mass of lithium (Li) is approximately 6.94 g/mol.
Mass of lithium produced:
0.0206 mol × 6.94 g/mol ≈ 0.143 g
Therefore, approximately 0.143 grams of lithium metal would be produced when 0.500 grams of magnesium is added to a solution of lithium chloride.