if the radius of a neutron is 1.0 x 10 minus 13cm calculate the density of a neutron in g/cm 3

What's the shape of a neutron. I suppose we are to assume it is a sphere but no one has ever seen one so who knows?

volume = (4/3)*pi*r^3
Then density = mass/volume.
Look up the mass of a neutron. You do the math.

To calculate the density of a neutron, we need to know its mass and volume.

1. The mass of a neutron is approximately 1.675 x 10^(-24) grams.

2. The volume of a neutron can be calculated using its radius. The volume of a sphere is given by the formula V = (4/3)πr³, where r is the radius of the sphere.

Plugging in the given radius of 1.0 x 10^(-13) cm into the formula, we get:
V = (4/3) * π * (1.0 x 10^(-13))^3 cm³

Evaluate the expression within the parentheses:
V ≈ (4/3) * π * (1.0 x 10^(-13))^3 cm³
V ≈ (4/3) * π * (1.0 x 10^(-39)) cm³
V ≈ (4/3) * π * 1.0 x 10^(-39) cm³
V ≈ 4/3 * 3.14159 * 1.0 x 10^(-39) cm³
V ≈ 4.18879 x 10^(-39) cm³

3. Now that we have both the mass and volume of the neutron, we can calculate its density using the formula:
Density = mass / volume

Plugging in the values, we get:
Density = 1.675 x 10^(-24) grams / 4.18879 x 10^(-39) cm³

Divide the numeric values and simplify the exponents:
Density ≈ (1.675 / 4.18879) x 10^(-24 - (-39)) grams/cm³
Density ≈ 0.40008 x 10^(15) grams/cm³

Convert the result into standard scientific notation:
Density ≈ 4.0008 x 10^(14) grams/cm³

Therefore, the density of a neutron is approximately 4.0008 x 10^(14) grams/cm³.