A tank contains Ar at 1.33 atm and Kr at 3.59 atm. We add enough Xe to give a total pressure of 6.3 atm. What is the partial pressure of the Xe?
pAr + pKr + pXe = Ptotal.
You know all but one. Solve for that one
To find the partial pressure of Xe in the tank, we need to use Dalton's Law of Partial Pressures. According to this law, the total pressure exerted by a mixture of gases is equal to the sum of the pressures of each gas in the mixture.
In this case, the total pressure of the mixture is given as 6.3 atm. The partial pressure of argon (Ar) is given as 1.33 atm, and the partial pressure of krypton (Kr) is given as 3.59 atm. We need to determine the partial pressure of xenon (Xe).
To find the partial pressure of Xe, we can subtract the sum of the partial pressures of Ar and Kr from the total pressure.
Partial pressure of Xe = Total pressure - (Partial pressure of Ar + Partial pressure of Kr)
Partial pressure of Xe = 6.3 atm - (1.33 atm + 3.59 atm)
Partial pressure of Xe = 6.3 atm - 4.92 atm
Partial pressure of Xe = 1.38 atm
Therefore, the partial pressure of Xe in the mixture is 1.38 atm.