what will be the boiling point 54.5 grams of aluminum sulfate dissolved in 805 grams H2O
mols Al2(SO4)3 = grams/molar mass.
molality = mols from above/kg solvent.
delta T = i*Kb*m
You know m, look up Kb, i = 5 for Al2(SO4)3, solve for delta T, then add to 100 for the new boiling point.