Whats the balanced net ionic equation for Chlorine reduced by Bromine?
Cl2 + 2Br- -> 2Cl- + Br2
Write what you know and explain, in detail, what you don't understand about the problem.
I figured the equation, but I just wasn't really sure about the states.
From what I know Cl2 and Br2 could be (aq) or (g) and the 2Br- and 2Cl- should be both (aq). But I'm not really sure.
Oh okay. Could Cl2 be (aq) though? Like dissolved in water as a molecule?
To determine the balanced net ionic equation for chlorine being reduced by bromine, we need to consider the oxidation states and the chemical reaction involved.
First, let's write the chemical equation for this reaction:
Cl2 + Br- → Cl- + Br2
This equation shows that chlorine (Cl2) is being reduced by bromine ion (Br-) to form chloride ion (Cl-) and bromine (Br2).
Next, we will assign the oxidation states to each element in the equation. The oxidation state of chlorine is 0 because it is in its elemental form (Cl2). The oxidation state of bromine is -1 because it is in the form of the bromine ion (Br-). The oxidation state of chloride is -1 because it is an ion (Cl-). Lastly, the oxidation state of bromine is 0 because it is in its elemental form (Br2).
Now, we can write the equation using the assigned oxidation states:
Cl2 + 2Br- → 2Cl- + Br2
Finally, we can simplify the equation to the balanced net ionic equation by canceling out the spectator ions (ions that are present on both sides of the equation and do not participate in the reaction). In this case, the spectator ions are the chloride ions (Cl-). After canceling them out, we get the balanced net ionic equation:
Cl2 + 2Br- → Br2
You didn't ask the question correctly AND you still seem to be confused in your response. Cl2 does not react with bromine. Cl2 will react with broMIDE ion and that is the equation written by DrWLS. Cl2 is gas. Br2 is a liquid. BromIDE is an aqueous solution of sodium bromide, potassium bromide, and such. If you want to go with the equation as written by DrWLS, it will be
Cl2(g) + 2Br^-(aq) ==> Br2(l) + 2Cl^-(aq)