which of the following is formed when CH3ONa is heated with C2H5I :
1 dimethly ether
2 ethly methly ether
3 methyl propyl ether
4 diethyl ether
help plz
To determine the product formed when CH3ONa is heated with C2H5I, we need to consider the reaction between these two compounds. CH3ONa is sodium methoxide, a strong base, while C2H5I is ethyl iodide, an alkyl halide.
The reaction between a strong base and an alkyl halide is known as an elimination reaction, specifically the Williamson ether synthesis. In this reaction, the alkyl halide loses the halogen atom and the base removes a proton from the alkyl group, resulting in the formation of an ether.
Let's analyze the possible options:
1. Dimethyl ether: This option does not involve the use of C2H5I, so it is not formed in this reaction.
2. Ethyl methyl ether: This option involves ethyl iodide, C2H5I. This alkyl halide reacts with CH3ONa as the base, resulting in the elimination of iodine and the formation of ethyl methyl ether. Therefore, this is the correct option.
3. Methyl propyl ether: This option does not involve the use of CH3ONa, so it is not formed in this reaction.
4. Diethyl ether: This option involves the use of two molecules of CH3ONa, so it is not formed in this reaction.
Therefore, the correct answer is 2) ethyl methyl ether.