kaylin throws two dice. the difference in face value between the two dice is three, and the product of the numbers thrown is equal to twice the sum of two numbers. Write and solve an algebraic equation that finds the numbers kaylin threw.
x-y=3 ---> x = y+3
xy = 2(x+y)
xy = 2x + 2y
y(y+3) = 2(y+3) + 2y
y^2 + 3y = 2y + 6 + 2y
y^2 - y - 6 = 0
(y-3)(y+2) = 0
y = 3 or -2, but y>0
y = 3, then x = 6
she threw a 3 and a 6