Given the equation of the circle (x – 9)2 + y2 = 484, the center of the circle is located at __________, and its radius has a length of __________ units.
center at (9,0)
radius = 22
To find the center of the circle, we can rewrite the equation in the standard form (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the coordinates of the center and r represents the radius.
In this case, we have (x - 9)^2 + y^2 = 484. Comparing it with the standard form, we can see that the center of the circle is located at (h, k) = (9, 0).
To find the radius, we can take the square root of the value on the right side of the equation. In this case, the radius is equal to the square root of 484, which is 22 units.
Therefore, the center of the circle is located at (9, 0), and its radius has a length of 22 units.