what is the result when 2x^2+3xy-6 is subtracted from x^2-7xy+2? show your work. please help me!

Well, let's solve this math problem while having a laugh!

To subtract 2x^2+3xy-6 from x^2-7xy+2, we need to subtract the corresponding coefficients of the variables.

Starting off with the x^2 terms:

x^2 - 2x^2 = -x^2

Next, let's look at the xy terms:

-7xy - 3xy = -10xy

Finally, let's handle the constant terms:

2 - (-6) = 8

So, when subtracting 2x^2+3xy-6 from x^2-7xy+2, the result is -x^2 - 10xy + 8.

Remember, math can be serious, but there's always room for a chuckle along the way!

To subtract 2x^2 + 3xy - 6 from x^2 - 7xy + 2, we need to subtract like terms.

We begin by subtracting the x^2 terms:

x^2 - (2x^2) = x^2 - 2x^2 = -x^2

Next, we subtract the xy terms:

-7xy - (3xy) = -7xy - 3xy = -10xy

Lastly, we subtract the constant terms:

2 - (-6) = 2 + 6 = 8

Therefore, the result of subtracting 2x^2 + 3xy - 6 from x^2 - 7xy + 2 is:

-x^2 - 10xy + 8

To subtract the expression 2x^2 + 3xy - 6 from x^2 - 7xy + 2, we need to combine like terms.

First, let's rearrange the terms in both expressions:

Original expression: x^2 - 7xy + 2
Expression to be subtracted: - (2x^2 + 3xy - 6)

Now, let's distribute the negative sign across all terms in the expression to be subtracted:

-2x^2 - 3xy + 6

Next, we can combine like terms by adding or subtracting coefficients of similar variables. In this case:

x^2 - 2x^2 = -x^2
-7xy - (-3xy) = -7xy + 3xy = -4xy
2 - 6 = -4

Putting it all together, the result of subtracting 2x^2 + 3xy - 6 from x^2 - 7xy + 2 is:

-x^2 - 4xy - 4

(x^2 - 7xy + 2)-(2x^2 + 3xy -6)

subtract each term with the same exponent, if there was an exponent value without a matching value in the other equation you would leave it alone
*do not forget to subtract each time!

-x^2 - 10xy + 8

x ^ 2 - 7 x y + 2 - ( 2 x ^ 2 + 3 x y - 6 ) =

x ^ 2 - 2 x ^ 2 - 7 x y - 3 x y + 2 - ( - 6 ) =

- x ^ 2 - 10 x y + 2 + 6 =

- x ^ 2 - 10 x y + 8