what is the result when 2x^2+3xy-6 is subtracted from x^2-7xy+2? show your work. please help me!
Well, let's solve this math problem while having a laugh!
To subtract 2x^2+3xy-6 from x^2-7xy+2, we need to subtract the corresponding coefficients of the variables.
Starting off with the x^2 terms:
x^2 - 2x^2 = -x^2
Next, let's look at the xy terms:
-7xy - 3xy = -10xy
Finally, let's handle the constant terms:
2 - (-6) = 8
So, when subtracting 2x^2+3xy-6 from x^2-7xy+2, the result is -x^2 - 10xy + 8.
Remember, math can be serious, but there's always room for a chuckle along the way!
To subtract 2x^2 + 3xy - 6 from x^2 - 7xy + 2, we need to subtract like terms.
We begin by subtracting the x^2 terms:
x^2 - (2x^2) = x^2 - 2x^2 = -x^2
Next, we subtract the xy terms:
-7xy - (3xy) = -7xy - 3xy = -10xy
Lastly, we subtract the constant terms:
2 - (-6) = 2 + 6 = 8
Therefore, the result of subtracting 2x^2 + 3xy - 6 from x^2 - 7xy + 2 is:
-x^2 - 10xy + 8
To subtract the expression 2x^2 + 3xy - 6 from x^2 - 7xy + 2, we need to combine like terms.
First, let's rearrange the terms in both expressions:
Original expression: x^2 - 7xy + 2
Expression to be subtracted: - (2x^2 + 3xy - 6)
Now, let's distribute the negative sign across all terms in the expression to be subtracted:
-2x^2 - 3xy + 6
Next, we can combine like terms by adding or subtracting coefficients of similar variables. In this case:
x^2 - 2x^2 = -x^2
-7xy - (-3xy) = -7xy + 3xy = -4xy
2 - 6 = -4
Putting it all together, the result of subtracting 2x^2 + 3xy - 6 from x^2 - 7xy + 2 is:
-x^2 - 4xy - 4
(x^2 - 7xy + 2)-(2x^2 + 3xy -6)
subtract each term with the same exponent, if there was an exponent value without a matching value in the other equation you would leave it alone
*do not forget to subtract each time!
-x^2 - 10xy + 8
x ^ 2 - 7 x y + 2 - ( 2 x ^ 2 + 3 x y - 6 ) =
x ^ 2 - 2 x ^ 2 - 7 x y - 3 x y + 2 - ( - 6 ) =
- x ^ 2 - 10 x y + 2 + 6 =
- x ^ 2 - 10 x y + 8