what is the electric field at the position 20 cm from Q2 and 60 cm from Q1?
Q2=40 micro coulombs
Q1=20 micro coulombs
Q2 and Q1 are separated by 80 cm
60 cm or 80 cm ?????
If 80 cm =0.8 m , then
F = k•q1•q2/r² =
=9•10^9•40•10^-6•20•10^-6/0.8^2 = ...
no elena i believe quinton is looking for the electric field positions of Q2 and Q1 separately at different distances from each respectively
Sorry.
E = k•q/r^2
E1 = k•q1/r1^2 = 9•10^9•40•10^-6/(0.2)^2 =6•10^6 V/m,
E2 = k•q2/r2^2 = 9•10^9•60•10^-6/(0.6)^2 = 1.5•10^6 V/m,
E =E1 – E2 = 4.5•10^6 V/m.
thank you very much guys..i really appreciate it.
To find the electric field at a specific point, you can use the principle of superposition. The total electric field at a point is the vector sum of the electric fields produced by each individual charge.
Given that Q2 = 40 μC, Q1 = 20 μC, and the distance between them is 80 cm, we can find the electric field at the two specified positions:
1. Electric field at 20 cm from Q2 and 60 cm from Q1:
To find the electric field at this position, we need to consider the contributions from both charges.
The electric field due to Q2 can be calculated using Coulomb's law:
E2 = k * Q2 / r^2,
where k is the electrostatic constant (k ≈ 8.99 x 10^9 N m^2/C^2) and r is the distance from the charge Q2 to the point of interest.
Plugging in the values, we have:
E2 = (8.99 x 10^9 N m^2/C^2 * 40 x 10^-6 C) / (0.2 m)^2.
Similarly, we can calculate the electric field due to Q1:
E1 = k * Q1 / r^2,
where r is the distance from Q1 to the point of interest.
Plugging in the values, we have:
E1 = (8.99 x 10^9 N m^2/C^2 * 20 x 10^-6 C) / (0.6 m)^2.
To find the total electric field at this point, we need to sum the individual electric fields:
E_total = E1 + E2.
2. Electric field at 20 cm from Q2 and 60 cm from Q1:
The steps are similar to the previous case, but in this scenario, we are considering the electric field at a different position.
Again, starting with the electric field due to Q2:
E2 = (8.99 x 10^9 N m^2/C^2 * 40 x 10^-6 C) / (0.2 m)^2.
And the electric field due to Q1:
E1 = (8.99 x 10^9 N m^2/C^2 * 20 x 10^-6 C) / (0.6 m)^2.
The total electric field at this point is the sum of the individual electric fields:
E_total = E1 + E2.
By employing these calculations, you can determine the magnitude and direction of the electric field at the specified positions.