consider 400 mL of a0.266 M LiNO3 solution. To what volume must it be diluted to make a 0.075 M LiNO3 solution.
Use the dilution formula of
c1v1 = c2v2
c = concn
v = volume.
0.266 x 0.400/0.075= 1.42 L
To calculate the volume of solvent (usually water) needed to dilute a solution, you can use the formula for dilution:
C1V1 = C2V2
where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
In this case, you have:
C1 = 0.266 M (initial concentration)
V1 = 400 mL (initial volume)
C2 = 0.075 M (final concentration)
V2 = ? (final volume, what we need to find)
Plugging these values into the equation, we get:
(0.266 M)(400 mL) = (0.075 M)(V2)
To solve for V2, we rearrange the equation:
V2 = (0.266 M)(400 mL) / (0.075 M)
Now let's calculate V2:
V2 = (0.266 × 400) / 0.075 = 1418.67 mL
Therefore, you would need to dilute the 400 mL of 0.266 M LiNO3 solution to a final volume of approximately 1418.67 mL (or 1.42 L) to obtain a 0.075 M LiNO3 solution.