A 500 ml bottle of 16 M hydrocholric acid is diluted to a final volume of 5,0 liters .. what is the concentration of the new diluted , HLC sloution
Hydrochloric acid is HCl, not HLC.
16 M x (500/5,000) = ? M
To calculate the concentration of the new diluted HCl solution, we can use the formula:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given:
C1 = 16 M
V1 = 500 ml = 500/1000 = 0.5 L
V2 = 5.0 L
Let's substitute these values into the formula and solve for C2:
C1V1 = C2V2
16 M * 0.5 L = C2 * 5.0 L
8 M = C2 * 5.0 L
C2 = 8 M / 5.0 L
C2 ≈ 1.6 M
Therefore, the concentration of the new diluted HCl solution is approximately 1.6 M.
To find the concentration of the new diluted hydrochloric acid (HCl) solution, we can use the equation for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration (16 M)
V1 = initial volume (500 ml or 0.5 liters)
C2 = final concentration (unknown)
V2 = final volume (5.0 liters)
Rearranging the equation, we have:
C2 = (C1V1) / V2
Substituting the given values, we get:
C2 = (16 M * 0.5 L) / 5.0 L
C2 = 8 M
Therefore, the concentration of the new diluted hydrochloric acid solution is 8 M.