Calculate the pH of a 2.5x10-5 M lithium hydroxide solution.
LiOH is a strong base; theefore, (OH^-) = (LiOH).
pOH = -log(OH^-), then
pH + pOH = pKw = 14
You know pOH and pKw, solve for pH.
To calculate the pH of a solution, we need to determine the concentration of hydroxide ions (OH-) in the solution. The hydroxide ion concentration can be determined from the concentration of the lithium hydroxide solution.
The lithium hydroxide (LiOH) dissociates into one lithium ion (Li+) and one hydroxide ion (OH-). Therefore, the concentration of OH- in the solution will be the same as the concentration of LiOH.
Given that the concentration of the lithium hydroxide solution is 2.5x10^-5 M, the concentration of hydroxide ions (OH-) is also 2.5x10^-5 M.
The pH of a solution can be calculated using the formula: pH = -log[H+], where [H+] is the concentration of hydrogen ions (H+).
In water, the concentration of hydroxide ions (OH-) and hydrogen ions (H+) are related by the equation: [H+] x [OH-] = 1x10^-14 M^2.
Since the concentration of hydroxide ions (OH-) is 2.5x10^-5 M, we can substitute this value into the equation to calculate [H+]: [H+] x 2.5x10^-5 M = 1x10^-14 M^2.
Rearranging the equation, we find: [H+] = (1x10^-14 M^2) / (2.5x10^-5 M).
Simplifying the expression, we get: [H+] = 4 x 10^-10 M.
Finally, we can calculate the pH by taking the negative logarithm of [H+]: pH = -log(4x10^-10) ≈ 9.4.
Therefore, the pH of the 2.5x10^-5 M lithium hydroxide solution is approximately 9.4.
To calculate the pH of a solution, we use the formula:
pH = -log[H+]
In this case, we are given the concentration of lithium hydroxide, which dissociates into lithium ions (Li+) and hydroxide ions (OH-) in water. Since lithium hydroxide is a strong base, it fully dissociates into its ions.
Lithium hydroxide dissociates as follows:
LiOH -> Li+ + OH-
Now, we need to determine the concentration of hydroxide ions (OH-) in the solution. Since lithium hydroxide's concentration is given as 2.5x10-5 M, we know the concentration of hydroxide ions will also be 2.5x10-5 M.
Next, we need to calculate the pOH, which is the negative logarithm of the hydroxide ion concentration:
pOH = -log[OH-]
pOH = -log(2.5x10-5) = 4.60
To find the pH, we use the fact that pH + pOH = 14:
pH = 14 - pOH = 14 - 4.60 = 9.40
Therefore, the pH of a 2.5x10-5 M lithium hydroxide solution is 9.40.