The 6th term of an A.P is twice the third and the first term is 3. Find the common difference and the 10th term.
3+5d = 2(3+2d)
3+5d = 6+4d
d = 3
So, the sequence is
3, 6, 9, 12, 15, 18, 21, 24, 27, 30 ...
as d=3
a10=3+(10-1)3
=30
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In an arithmetic sequence is eighth term is twice the fourth term the twenty term is 20 . common difference
3+5d=2(3+2d)
3+5d=6+4d
d=3
Imply formula to get the sequence