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The 9th term of an Arithmetic Progression is 8 and the 4th term is 20. Find the first term and the common difference.

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  1. There are 5 terms, with a total difference of -12, so d = -12/5

    a + 3(-12/5) = 20
    a - 36/5 = 20
    a = 136/5

    So, the sequence is

    136/5, 124/5, 112/5, 100/5=20, 88/5, 76/5, 64/5, 52/5, 40/5=8, ...

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  2. The sum of the 6 and 8 term of an ap is 142,if the 4 term is 49 calculate the first term

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