3. A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved?)
PE= q*delta V
solve for deltaV
To find the electric potential difference before and after the charge was moved, we need to use the equation that relates electric potential energy change (ΔPE) and the electric potential difference (ΔV).
The equation is given as:
ΔPE = q * ΔV
where ΔPE is the change in electric potential energy, q is the charge, and ΔV is the change in electric potential.
In this case, we are given that the charge q = 5.0 µC, and the change in electric potential energy ΔPE = 10.0 J.
Plugging these values into the equation, we can solve for ΔV:
10.0 J = (5.0 µC) * ΔV
To solve for ΔV, we need to convert the charge from microcoulombs (µC) to coulombs (C) by dividing by 1,000,000:
10.0 J = (5.0 * 10^-6 C) * ΔV
Now we can solve for ΔV:
ΔV = 10.0 J / (5.0 * 10^-6 C)
ΔV = 2.0 * 10^6 V
So, the electric potential difference before and after the charge was moved is 2.0 * 10^6 Volts (V).
To find the electric potential difference before and after the charge was moved, we can use the formula:
Electric Potential Difference = Electric Potential Energy Change / Charge
Given:
Electric potential energy change = 10.0 J
Charge = 5.0 µC = 5.0 × 10^-6 C
Using the formula, we can substitute the values:
Electric Potential Difference = 10.0 J / (5.0 × 10^-6 C)
Calculating this expression, we get:
Electric Potential Difference = 2.0 × 10^6 V
Therefore, the electric potential difference before and after the charge was moved is 2.0 × 10^6 volts.