SrH2 + 2 H2O ==> Sr(OH)2 + 2 H2
Determine the number of grams of strontium hydroxide (Sr(OH)2) produced when 10.0 g of hydrogen gas (H2) is also produced. (Your answer must have at least 3 significant figures.)
mols H2 gas = grams/molar mass
Convert mols H2 to mols Sr(OH)2 using the coefficients in the balanced equation.
Convert mols Sr(OH)2 to grams. g = mols x molar mass.
To determine the number of grams of strontium hydroxide (Sr(OH)2) produced, we need to use stoichiometry.
First, calculate the molar mass of hydrogen gas (H2). Hydrogen (H) has a molar mass of 1.01 g/mol, so the molar mass of H2 is 2.02 g/mol.
Next, use the balanced equation to determine the mole ratio between hydrogen gas (H2) and strontium hydroxide (Sr(OH)2). According to the balanced equation:
1 mole of SrH2 reacts with 2 moles of H2 to produce 1 mole of Sr(OH)2.
Now, use the mole ratio to convert the number of moles of H2 to moles of Sr(OH)2.
Moles of H2 = mass of H2 (in grams) / molar mass of H2
Moles of Sr(OH)2 = Moles of H2 x (1 mole Sr(OH)2 / 2 moles H2)
Substitute the given mass of hydrogen gas (H2) into the equation:
Moles of H2 = 10.0 g / 2.02 g/mol
Now, calculate the moles of Sr(OH)2:
Moles of Sr(OH)2 = (10.0 g / 2.02 g/mol) x (1 mol Sr(OH)2 / 2 mol H2)
Finally, calculate the mass of Sr(OH)2 using the molar mass of Sr(OH)2 (which is the sum of the atomic weights of strontium, oxygen, and two hydrogens).
Mass of Sr(OH)2 = Moles of Sr(OH)2 x molar mass of Sr(OH)2
This calculation will provide you with the number of grams of strontium hydroxide (Sr(OH)2) produced when 10.0 g of hydrogen gas (H2) is also produced.