If you do 12 J of work to push 0.001 C of charge from point A to point B in an electric field, what is the voltage difference between points A and B?
W = q•Δφ,
Δφ =W/q
To determine the voltage difference between points A and B, you need to use the equation:
V = W / Q
where V is the voltage difference, W is the work done, and Q is the charge moved.
In this case, the work done is 12 J and the charge moved is 0.001 C. Plugging these values into the equation:
V = 12 J / 0.001 C
To perform the division, make sure the units cancel out correctly.
1 C = 1 A * 1 s, so 0.001 C = 0.001 A * 1 s
V = 12 J / (0.001 A * 1 s)
The s in the denominator cancels with the s in the numerator, giving:
V = 12 J / 0.001 A
Now, dividing 12 J by 0.001 A:
V = 12000 V
Therefore, the voltage difference between points A and B is 12000 volts.