There are 2 red cars and 3 blue cars. The 5 cars contain a total of 12 people. No car has more than 4 people. Every car has at least 1 person. The only cars with the same number of people are the red cars. How many people are in 1 red car?
3 because 3+3=6+2+2+2=12
Looking at the problem, I see that that the plausible answers could be either 2 or 3. See the chart below for why:
2
4 in red cars (2 each)
8 left over
And you could use 1,4, and 3 for your numbers (since no blue car should have the same number of people in it)
for 3:
3
6 in red cars (3 each)
6 left over
And you could use 1,2, and 3 for your numbers (since no blue car should have the same number of people in it)
both answers follow each rule as shown:
-no car has more than 4 people
-every car has at least 1 person
-the only cars with the same number of people are the red cars
which concludes to the answer being 2 or 3
Im sorry. looking at the answer and question again I see that the answer couldn't possibly even be 3. It would have to be 2 because looking at my previous answer, i said you could use 1,2, and 3 for your numbers on the blue cars, when really you can't because 3 was the number for the red cars and you can't have the same numbers for blue and red, as it says only red cars have the same number of people. Sorry for the mishap:) the answer is 2
Im sorry. looking at the answer and question again I see that the answer couldn't possibly even be 3. It would have to be 2 because looking at my previous answer, i said you could use 1,2, and 3 for your numbers on the blue cars, when really you can't because 3 was the number for the red cars and you can't have the same numbers for blue and red, as it says only red cars have the same number of people. Sorry for the mishap:) the answer is 2
To solve this problem, let's first define the number of people in one red car as "x". Since both red cars have the same number of people, we can use "x" for each of them.
We know that there are 2 red cars, so the total number of people in the red cars combined is 2x.
We also know that there are 3 blue cars, so the total number of people in the blue cars combined is 3y, where "y" represents the number of people in one blue car.
The total number of people in all the cars is given as 12, so we can write the equation:
2x + 3y = 12
Now, we need to consider the constraints mentioned in the problem. No car has more than 4 people, which means that both x and y must be less than or equal to 4. Also, every car has at least 1 person, so both x and y must be greater than or equal to 1.
Now, we can solve the equation using trial and error or substitution to find the values of x and y that satisfy the conditions. Let's start with trial and error:
If we assume that x is 1, then 2(1) + 3y = 12
Simplifying, we get 2 + 3y = 12
Subtracting 2 from both sides, we get 3y = 10
Dividing both sides by 3, we get y = 10/3, which is not a whole number and violates the constraint.
If we assume that x is 2, then 2(2) + 3y = 12
Simplifying, we get 4 + 3y = 12
Subtracting 4 from both sides, we get 3y = 8
Dividing both sides by 3, we get y = 8/3, which is not a whole number and violates the constraint.
If we assume that x is 3, then 2(3) + 3y = 12
Simplifying, we get 6 + 3y = 12
Subtracting 6 from both sides, we get 3y = 6
Dividing both sides by 3, we get y = 2
Therefore, the number of people in one red car (x) is 3.