A 50kg barrel of Bud is rolled up a 10 meter ramp to the back of the truck.The ramp makes a 30degree angle with the ground.

What is the potential energy of the barrel at the top of the ramp?
How uch work was done against gravity to get it to the top of the ramp?

h = s•sinα =10•0.5 = 5 m

PE = m•g•h =50•9.8•5=2450 J.
W =ΔPE =2450 J.

To calculate the potential energy of the barrel at the top of the ramp, we need to use the formula:

Potential Energy = mass * gravity * height

Given that the mass of the barrel is 50 kg and the height is 10 meters, let's calculate the potential energy:

Potential Energy = 50 kg * 9.8 m/s² * 10 m
Potential Energy = 4900 kg·m²/s² or 4900 J (Joules)

Therefore, the potential energy of the barrel at the top of the ramp is 4900 Joules.

To calculate the work done against gravity to get the barrel to the top of the ramp, we need to use the same formula but with the height of the ramp:

Work = mass * gravity * height

Given that the mass of the barrel is still 50 kg and the height of the ramp can be determined using trigonometry, let's calculate the work done:

Height of the ramp = ramp length * sin(angle)

Given that the ramp length is 10 meters and the angle is 30 degrees, let's calculate the height of the ramp:

Height of the ramp = 10 m * sin(30°)
Height of the ramp = 10 m * 0.5
Height of the ramp = 5 m

Now, let's calculate the work done:

Work = 50 kg * 9.8 m/s² * 5 m
Work = 2450 kg·m²/s² or 2450 J (Joules)

Therefore, the work done against gravity to get the barrel to the top of the ramp is 2450 Joules.