Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 11.0 cm and b = 23.0 cm. (Indicate the direction with the sign of your answer. Assume that the positive direction is counterclockwise.)
Elena did the right calcutions, she just got wrong the signs
The torque produced by the 10 N force is
τ = 10 • 0.23 = - 2.3 (N m),
The torque produced by the 9 N force is
τ = 9 • 0.23 = - 2.07 (N m),
The torque produced by the 12 N force is
τ = 12 • 0.11 = + 1.32 (N m)
The total torque is
τ =- 2.3 - 2.07 +1.32 = - 3.05 (N m)
Elena is right you all just need to change the sign to negative
Elena you need to do better
Sup guys
Cmon Elena
To find the net torque on the wheel in the figure, we need to consider the torques caused by each force acting on the wheel.
The torque (τ) can be calculated using the formula: τ = force x lever arm, where the lever arm is the perpendicular distance from the axis of rotation to the line of action of the force.
In this case, there are two forces that contribute to the torque:
1. The force F1 acting tangentially on the wheel at point A.
2. The force F2 acting tangentially on the wheel at point B.
The perpendicular distance from the axis of rotation O to the line of action of F1 is a = 11.0 cm. This is the lever arm for F1.
The perpendicular distance from the axis of rotation O to the line of action of F2 is b = 23.0 cm. This is the lever arm for F2.
Now, we need to determine the direction of the torques. The problem states that the positive direction is counterclockwise. This means that any torque that tends to rotate the object counterclockwise is positive, while a torque that rotates it clockwise is negative.
The torque caused by force F1 can be calculated as τ1 = F1 * a.
The torque caused by force F2 can be calculated as τ2 = F2 * b.
To find the net torque, we need to sum up the individual torques and take their signs into account:
Net torque = τ1 + τ2
Remember, since the problem specifies that the positive direction is counterclockwise, any counterclockwise torque will be positive, while any clockwise torque will be negative.
Pakopya guys, di ko magets si sir Daryl
difficult
The torque produced by the 10 N force is
τ = 10 •0.23 = 2.3 (N•m),
The torque produced by the 9 N force is
τ = 9 •0.23 = 2.07 (N•m),
The torque produced by the 12 N force is
τ = 12 •0.11 = - 1.32 (N•m)
The total torque is
τ =2.3 + 2.07 -1.32 = 3.5 (N•m).